Question

Light travels through a substance at 1.97 x 10^8 m/s. What is the index of the liquid? What type of liquid is it?

Answer 1

n = 1.52

Index of the liquid = 1.52

The type of the liquid is Crown glass.

Step-by-step explanation:

In finding the index of refraction, we use this formula

n = c/v

where n is the index of refraction

c is velocity of light in vacuum which is constant and is equivalent to
`3 * 10^(8) \mathrm{m} / \mathrm{s}`

v is the velocity of light in a particular medium

Here we use
`1.97 * 10^(8) \mathrm{m} / \mathrm{s}`

Using the formula,

n = c/v

n =
`3 * 10^(8) / 1.97 * 10^(8)`

n = 1.52284264

n = 1.52

Thus, the index of the liquid is 1.52

Answer 2

The refractive index of the liquid is 1.52. The substance is a crown glass.

Step-by-step explanation:

Given:

Velocity of light through the substance, v = 1.97 X 10⁸ m/s

Refractive index of the liquid, μ = ?

We know,

μ =
`(c)/(v)`

where, c = velocity of light in air

v = velocity of light in the substance

speed of light in air is 3 X 10⁸m/s

`= (3 X 10^8)/(1.97 X 10^8) \\\\= 1.52\\`

Therefore, refractive index of the liquid is 1.52. The substance is a crown glass.