Question

If you shine a laser on two slits with a separation of 0.215 mm, and the diffraction pattern shines on a background 4.90 m away, what is the wavelength of the laser light if the fringes are separated by 1.60 cm

Answer 1

`\lambda = 702\ nm`

Step-by-step explanation:

Given,

slit width, d = 0.215 mm

slit separation, D = 4.90 m

Wavelength of the laser light = ?

Fringe width.
`\beta = 1.60\ cm`

Using formula

`\beta =(\lambda D)/(d)`

`\lambda=(\beta d)/(D)`

`\lambda=(0.016* 0.215* 10^(-3))/(4.90)`

`\lambda = 7.02* 10^(-9)\ m`

`\lambda = 702\ nm`

Wavelength of the laser light =
`\lambda = 702\ nm`