Question

A normal human heart, beating about once per second, creates a maximum 4.00 mV potential across 0.250 m of a person's chest, producing a 1.00 Hz electromagnetic wave. What is the maximum electric field strength produced?

Answer 1

Step-by-step explanation:

Potential difference, V = 4 mV = 0.004 V

distance, d = 0.25 m

The relation between the electric field strength and the potential difference is given by

V = E x d

0.004 = E x 0.25

E = 0.016 V/m

Thus, the maximum value of the electric field is 0.016 V/m.

Answer 2

maximum electric strength is 0.016 V/m

Step-by-step explanation:

given data

Potential V = 4 mV = 4 ×
`10^(-3)` V

potential across = 0.250 m

Frequency f = 1 Hz

solution

we get here electric field that is

E =
`(V)/(d)` ...................1

put here value and we get

E =
`(4* 10^(-3))/(0.250)`

E = 0.016 V/m

maximum electric strength is 0.016 V/m