Question

KATZPSEF1 30.P.041. My Notes Ask Your Teacher A charged particle enters a region of space with a uniform magnetic field B = 1.98 i T. At a particular instant in time, it has velocity v = (1.46 ✕ 106 i + 2.42 ✕ 106 j) m/s. Based on the observed acceleration, you determine that the force acting on the particle at this instant is F = 1.60 k N. What are the following?(a) the sign of the charged particle

(b) the magnitude of the charged particle

Answer 1

Answer: The charge on the particle is positive

While the magnitude = 0.00028C

Step-by-step explanation:

Please find the attached file for the solution