Question

Write an equation in slope-intercept form for a line parallel to the equation y = 4x+10 and contains the point (-2,5).

Answer 1

Answer: y = 4x + 13

Explanation:

y = 4x + 10

First find the slope m

y = mx + C

y - intercept point y

m - slope

x - intercept point x

C - intercept point

From the equation,

slope m = 4

Using the formula for slope

y - y_1 = m(x - x_1)

Given point ( -2 , 5)

x_1 = -2

y_1 = 5

m = 4

Inserting the values given

y - 5 = 4 ( x -(-2))

y - 5 = 4(x + 2) ( point slope form)

y - 5 = 4x + 8

y = 4x + 8 + 5

y = 4x + 13 ( slope-intercept form)

y = mx + C ( slope - intercept form formulae)