Question

Find the value of c that makes each trinomial a perfect square
x^2-19x+c
Please Help! :)

Answer 1

The value of c is
`(361)/(4)`

Step-by-step explanation:

Given that the trinomial is
`x^2-19x+c`

We need to determine the value of c such that the trinomial is a perfect square.

The value of c can be determined using the formula,

`c=((b)/(2))^2`

From the trinomial, the value of b is given by

`b=-19`

Substituting the value of b in the above formula, we have,

`c=((-19)/(2) )^2`

Squaring both the numerator and denominator, we have,

`c=(361)/(4)`

Thus, the value of c is
`(361)/(4)` which makes the trinomial a perfect square.