Question

Determine the magnitude of the net magnetic field at a point 1.3 m to the side of one wire and 3.9 m from the other wire. The point is in the same plane as the wires. Express your answer with the appropriate units.

Answer 1

Incomplete question.Here is complete question

Two long, parallel wires are separated by 2.0 m. Each wire has a 30-A current, but the currents are in opposite directions.(a) Determine the magnitude of the net magnetic field midway between the wires.(b) Determine the magnitude of the net magnetic field at a point 1.3 m to the side of one wire and 3.9 m from the other wire. The point is in the same plane as the wires. Express your answer with the appropriate units.

Answer:

`(a) B=12*10^(-6)T\\\\\\(b)B_(net)=3.1*10^(-6)T`

Step-by-step explanation:

Given data

`d_(wire)=2.0m\\I_(1,2)=30A`

The current flow in wire is opposite

The direction of magnetic field is the same between two wires

For Part (a)

`B=2*u(I)/(2\pi r)\\ B=2*(4\pi *10^(-7))(30)/(2\pi ((2)/(2) )) \\B=12*10^(-6)T`

For Part (b)

The magnetic field at this point will be sum of the magnetic field of each wire

`B_(1)=u(I)/(2\pi r) \\B_(1)=(4\pi *10^(-7))(30)/(2\pi (1.3))\\ B_(1)=4.615*10^(-6)T\\\\\\B_(2)=u(I)/(2\pi r)\\B_(2)=(4\pi *10^(-7))(30)/(2\pi (3.9))\\B_(2)=1.5385*10^(-6)T\\\\B_(net)=B_(1)-B_(2)\\B_(net)=4.615*10^(-6)T-1.5385*10^(-6)T\\B_(net)=3.1*10^(-6)T`