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A good baseball pitcher can throw a baseball toward home plate at 93 mi/h with a spin of 1510 rev/min. How many revolutions does the baseball make on its way to home plate? For simplicity, assume that the 60 ft path is a straight line.

1 Answer

3 votes

Answer:


\Delta \theta =11.073\ rev

Step-by-step explanation:

Given,

Speed of baseball = 93 mi/h

spin = 1510 rev/min


\Delta x = 60\ ft


v =93*  (88)/(60) = 136.4 ft/s


\omega = 1510* (1)/(60)= 25.167\ rad/s


\Delta t = (\Delta x)/(v)


\Delta t = (60)/(136.4 )


\Delta t = 0.44\ s

Revolutions of ball


\Delta \theta = \omega t


\Delta \theta = 25.167* 0.44


\Delta \theta =11.073\ rev

Revolution of the ball is equal to
\Delta \theta =11.073\ rev.

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