Answer:
y = 2x + 0
y = mx + C - equation of the line
Explanation:
First, find the slope
x + 3y = 9
Using the equation of line
y = mx + C
3y = 9 - x
3y = -x + 9
Divide both sides by 3
3y / 3 = ( -x + 9) / 3
y = ( -x + 9) / 3
We can separate it
y = -x/3 + 9/3
y = -x/3 + 3
m = -1/3
Slope = -1/3
Since weve gotten our slope
Let's use the equation of point slope form
y - y_1 = m(x - x_1)
We are provided with a point
( 1, 3)
x_1 = 1
y_1 = 3
If two lines are perpendicular, their slope will be negative reciprocal
m = -1/3
Perpendicular = +3/1
insert the values
y - 3 = 3(x - 1)
y - 3 = 3x - 3
y = 3x - 3 + 3
-3 cancels +3
y = 3x + 0