Question

Two volatile liquids A (P A pure= 165 Torr) and B (PB pure= 85.1 Torr) are confined in a piston/cylinder assembly. Initially only the liquid phase is present. As the external pressure is reduced, vapor is first observed at a total pressure of 110 Torr. Calculate the mole fraction of component A in the solution (XA) and the mole fraction of component A in the vapor (YA).

Answer 1

`y_A=0.467\\x_A=0.312`

Step-by-step explanation:

Hello,

In this case, one could use the following equations to compute the required mole fractions (fugacity equality for both A and B):

`p_A^(vap)x_A=y_AP\\p_B^(vap)(1-x_A)=(1-y_A)P\\p_B^(vap)-x_Ap_B^(vap)=P-y_AP\\y_AP-x_Ap_B^(vap)=P-p_B^(vap)`

Therefore, the 2x2 system of equations turns out:

`\left \{ {{165x_A-110y_A=0} \atop {110y_A-85.1x_A=24.9}} \right.\\ \\y_A=0.467\\x_A=0.312`

Best regards.