Answer:
26.2 m/s
Step-by-step explanation:
We are given that
![\theta=17^(\circ)](https://img.qammunity.org/2021/formulas/physics/high-school/ux1oes1jl61e7da8he73e1e39xopmqpg1l.png)
Distance traveled by truck =s=120 m
Final speed of truck =v=0
We have to find the initial speed of truck.
![v^2-u^2=2gs sin\theta](https://img.qammunity.org/2021/formulas/physics/high-school/a7rkfig1wxfd6f24vlprh4mha10bbpl7ux.png)
Where g=
![-9.8 m/s^2](https://img.qammunity.org/2021/formulas/physics/high-school/jc1cxxlzqc8sy8oqevp67mnp382ve4phq8.png)
Substitute the values
![0-(u)^2=2(-9.8)(120)sin17](https://img.qammunity.org/2021/formulas/physics/high-school/rkd0pys7qyns5gaxzyk5k0fkrotndqjtzp.png)
![-u^2=-686.784](https://img.qammunity.org/2021/formulas/physics/high-school/aqsy7xo8zx73k7daj6uzjr2bv4tvlf199h.png)
![u^2=686.784](https://img.qammunity.org/2021/formulas/physics/high-school/cw8qq8ih03qh6yy08vf95j3jf9r3kss1tg.png)
![u=√(686.784)](https://img.qammunity.org/2021/formulas/physics/high-school/2v09aba0mdtsrgbqyo2kix4jbafvp9m2ss.png)
u=26.2 m/s
Hence, the initial velocity of truck=26.2 m/s