Answer:
32%
Step-by-step explanation:
The proportion of the recessive sickle cell anemia allele in the given population is 20%. So, the frequency of the recessive allele in the population would be 20% or 0.2.
The population is said to be following the ideal equilibrium of alleles. Therefore, the frequency of the corresponding dominant allele for the locus would be= 1- frequency of the recessive allele = 1- 0.2 = 0.8
The frequency of the heterozygous individuals in the population= 2 x proportion of the dominant allele in the population x frequency of the recessive allele = 2 x 0.8 x 0.2 = 0.32 or 32%