Answer:
Step-by-step explanation:
Butane is the 4th member of alkane series. It has 4 carbon atoms.
First write a balanced equation for the combustion of butane as follows;
2C4H10 + 13O2 ===> 8CO2 + 10H2O
from the balanced equation,
2C4H10 weigh 2[(12 x 4) + (1 x 10)]
=2(48 + 10)
= 116g
13O2 weigh 13(16 x 2)
=13 x 32
= 416g
8CO2 weigh 8[ 12+ (16 x 2)]
8 x (12 + 32)
352g
From the equation, 116g of buthane produced 352g of carbon dioxide
10g of buthane will produce 10×116÷352 =