Question

What is the molarity of a solution that contains 30. grams of naoh in 500. milliliters of solution?.

Answer 1

1.5 mol/L

Step-by-step explanation:

molarity = moles/litres

NaOH = 23 + 16 + 1 = 40 g/mol

`? \: mol \: naoh \: = 30 \: g \: naoh \: * \\ \\ (1 \: mol \: naoh)/(40 \: g \: naoh) = 0.75 \: mol \: naoh`

molarity = 0.75 mol NaOH ÷ 0.5 L = 1.5 mol/L NaOH