Question

A reaction was performed in which 0.55 g of 2-naphthol was reacted with a slight excess of 1-bromobutane to make 0.32 g of 2-butoxynaphthalene. Calculate the theoretical yield and percent yield for this reaction.

Answer 1

Without the balanced chemical equation and molar masses, the theoretical yield of 2-butoxynaphthalene cannot be calculated. Normally, it involves stoichiometric calculations from the starting material. Percent yield is obtained by dividing actual yield by theoretical yield and multiplying by 100%.

Step-by-step explanation:

To calculate the theoretical yield and percent yield for the given reaction, we need to perform a few stoichiometric calculations. However, without the balanced chemical equation and the molar masses, we cannot calculate the theoretical yield for the specific reaction of 2-naphthol and 1-bromobutane to form 2-butoxynaphthalene. If we had the balanced equation, we would calculate the moles of 2-naphthol used, and using stoichiometry, find the moles of 2-butoxynaphthalene that could be formed. Multiplying by the molar mass would give us the theoretical yield in grams. To find percent yield, we would then divide the actual yield (0.32 g) by the theoretical yield and multiply by 100.

Generally speaking, percent yield is the ratio of the actual yield to the theoretical yield multiplied by 100%. It indicates the efficiency of a chemical reaction and can be decreased by incomplete reactions, side reactions, or product recovery losses.

Answer 2

Theoretical yield=0.764 g.

Percent yield 42%.

Step-by-step explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture. In such a way, starting by the given mass of 2-naphtol, one computes the theoretical yielded grams of 2-butoxynaphthalene as shown below, considering their 1 to 1 molar relationship:

`m_(2-butoxynaphthalene)=0.55g2-naphtol*(1mol2-naphtol)/(144.17g2-naphtol)*(1mol2-butoxynaphthalene)/(1mol2-naphtol)*(200.28g2-butoxynaphthalene)/(1mol2-butoxynaphthalene)=0.764g2-butoxynaphthalene`

Moreover, the percent yield turns out:

`Y=(0.32g)/(0.764g)*100\% =42\%`

Best regards.