Question

A 21 L cylinder containing helium gas at a pressure of 47.9 atm is used to fill a weather balloon in order to lift equipment into the stratosphere. To what maximum pressure (in atm) could a 290 L balloon be filled.

Answer 1

To determine the maximum pressure at which a 290 L balloon can be filled, we can use Boyle's Law. Given the initial volume and pressure, we can set up an equation to solve for the final pressure. The maximum pressure is approximately 3.4569 atm.

Step-by-step explanation:

To determine the maximum pressure at which a 290 L balloon can be filled, we can use Boyle's Law. Boyle's Law states that the product of the initial volume and pressure is equal to the product of the final volume and pressure, as long as the temperature remains constant.

Given that we have a 21 L cylinder containing helium at a pressure of 47.9 atm, we can use these values as the initial volume and pressure. Let the final volume be 290 L and the final pressure be represented by P (in atm). Using Boyle's Law, we can set up the equation:

(21 L) * (47.9 atm) = (290 L) * P

Solving for P, we find:

P = (21 L * 47.9 atm) / 290 L

P = 3.4569 atm

Therefore, the maximum pressure at which the 290 L balloon can be filled is approximately 3.4569 atm.

Answer 2

3.5 atm

Step-by-step explanation:

Given data

• Initial pressure (P₁): 47.9 atm

• Initial volume (V₁): 21 L

• Final pressure (P₂): ?

• Final volume (V₂): 290 L

We can find the maximum pressure that the gas can exert (final pressure) using Boyle´s law.

P₁ × V₁ = P₂ × V₂

P₂ = P₁ × V₁ / V₂

P₂ = 47.9 atm × 21 L / 290 L

P₂ = 3.5 atm