Question

You wish to make a 0.299 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution?

Answer 1

`V_1=2.49mL`

Step-by-step explanation:

Hello,

In this case, considering that the moles of hydrioiodic acid remain unchanged during the dilution process:

`n_(HI)=n_(HI)`

One could apply the following equality in terms of molarity:

`V_1M_1=V_2M_2`

Whereas the subscript 1 accounts for the solution before the dilution and 2 after the dilution, therefore, the required volume of 6.00 M acid is:

`V_1=(V_2M_2)/(M_1) =(50.0mL*0.299M)/(6.00M)=2.49mL`

Best regards.