Question

The volume of a gas at 99.6 kPa and 24°C is 4.23 L. What volume will it occupy at 93.3 kPa ?

Answer 1

To find the new volume of the gas when the pressure changes from 99.6 kPa to 93.3 kPa, one applies Boyle's Law, resulting in a new volume of 4.53 L.

Step-by-step explanation:

The question involves using Boyle's Law, which states that for a given mass of ideal gas at constant temperature, the product of pressure and volume is constant. In the given example, the initial condition is a volume of 4.23 L of gas at a pressure of 99.6 kPa. When the pressure changes to 93.3 kPa, we want to find out what the new volume of the gas will be, assuming temperature and amount remain constant. We can use the equation:

P1 * V1 = P2 * V2

Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume respectively. Plugging in the initial conditions and solving for V2 gives us the formula:

V2 = (P1 * V1) / P2

Inserting the values:

V2 = (99.6 kPa * 4.23 L) / 93.3 kPa = 4.53 L

So the new volume of the gas will be 4.53 L after the pressure has been adjusted to 93.3 kPa.

Answer 2

The volume is increased to 4.52 L on decreasing the pressure to 93.3 kPa.

Step-by-step explanation:

As per Boyle's law, the volume occupied by gas particles will be inversely proportional to the pressure experienced by those particles at constant temperature.

`V=(1)/(P)`

So in the present problem, the volume of gas at pressure P₁ = 99.6 kPa is given as V₁ = 4.23 L. The temperature is kept constant at 24°C. Then, if the pressure is decreased to 93.3 kPa, then the volume is tend to increase due to Boyle's law.

So let us consider the new pressure be P₂ = 93.3 kPa and the new volume has to be found.

Then using Boyle's law,
`P_(1) V_(1) = P_(2) V_(2)`

Then,
`V_(2)=(P_(1) V_(1) )/(P_(2) )`

So,
`V_(2)=(99.6*1000*4.23)/(93.3*1000)=4.52 L`

Thus, the volume is increased to 4.52 L on decreasing the pressure to 93.3 kPa.