Question

Find the average value of f(x)=e^2x-2 on the interval [0,2].

Answer 1

Explanation:

f(0)=e^0-2=1-2=-1

f(1)=e²-2

f(2)=e^4-2

average value=(`-1+e²-2+e^4-2)/3=(e^4+e²-5)/3