Question

What is the equation of a line l that has an x-intercept of (5, 0) and is perpendicular to another line m that has a slope -5?

Question 14 options:


y = -5x+ 25


y= -5x + 5


y = 1/5 x + 5


y = 1/5 x - 1

Answer 1

`y=(1)/(5)x+5`

Explanation:

Slope of a perpendicular line is the "negative reciprocal" of the slope of the original line (i.e
`m=-5`)

∴
`m=-(1)/(-5)=(1)/(5)`

the slope-intercept form:
`y=mx+c`

with

`m=(1)/(5)`

and
`c=5`

is

`y=(1)/(5)x+5`