Question

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 5 minutes. Find the probability that a randomly selected passenger has a waiting time less than 1.75 minutes.

Answer 1

0.35

Explanation:

we know that

The formula to use for uniform distribution is equal to

`P( X < x) = (x-a)/(b-a)`

where,

b is the upper limit of the distribution which is 5 minutes in this case.

a is the lower limit of the distribution which is 0 minutes in this case.

x is the concerned value which is 1.75 minutes in this case.

substitute the given values

`P( X< 1.75) = (1.75-0)/(5-0)=0.35`

That means

The probability that a randomly selected passenger has a waiting time less than 1.75 minutes is 0.35