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Solve question number 21

Solve question number 21-example-1

1 Answer

2 votes

Answer:

∝ = 60.50°

Explanation:


AC = \sqrt{AB^(2) + BC^(2) } = √(128) \\\\AM = (AC)/(2) = (√(128) )/(2) \\\\

∡VAM = ∝


tg \alpha = (VM)/(AM) = (10)/((√(128) )/(2) ) = 1.76776695297 \\\\


\alpha = arctan (1.76776695297) = 60.50

User Carlo Pecchia
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