Question

Describe how you would prepare 2.44 kg of an aqueous solution that is 16.3% KOH by mass.

Describe how you would prepare 2.44 of an aqueous solution that is 16.3% by mass.
0.163 kg KOH. Add 0.163 kg KOH to 2.277 kg water.
2.44 kg solution x 0.163 = 0.40 kg KOH. Add 0.40 kg KOH to 2.84 kg water.
0.163 kg KOH. Add 0.163 kg KOH to 2.603 kg water.
2.44 kg solution x 0.163 = 0.40 kg KOH. Add 0.40 kg KOH to 2.04 kg water.
Request Answer

Answer 1

• Add 0.40 kg KOH to 2.04 kg water.

Step-by-step explanation:

The formula for mass percentage is:

• % (w/w) = (mass of solute / mass of solution) × 100

The data are:

• mass of solution: 2.44 kg
• % (w/w) = 16.3

Substitute and solve:

• 16.3 = ( x / 2.44kg ) × 100

• x = 16.3 ×2.44kg / 100 = 0.39772kg ≈ 0.40kg

Then, you will need to use 0.40kg of KOH and the amount of water needed to complete 2.44 kg of solution:

• water = 2.44kg - 0.40kg = 2.04kg

Conclusion

• Add 0.40kg of KOH to 2.04 kg of water.