Question

Can someone help me out asap tap on the picture​

Answer 1

`\large\boxed{\large\boxed{x=54\º}}`

Step-by-step explanation:

In the figure, two secants that intersect outside a circle form an angle with measure of xº and the measures of the arcs formed are 136º and 28º.

When two secants intersect outside a circle, the measure of the angle formed is one-half the absolute difference of the measures of the intercepted arcs.

Then, you can write and solve this equation:

`x=(1)/(2)(136\º-28\º)\\\\\\x=54\º`