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Find the zeros of y= x - 4x - 9 by completing the square.

O A. *= 2: 113
O B. x= 3+ /13
O c. *= +3
O D. x=-21,13

Find the zeros of y= x - 4x - 9 by completing the square. O A. *= 2: 113 O B. x= 3+ /13 O-example-1
User Lakshayg
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1 Answer

6 votes

The zeros for the given equation are A.
x = {2 \pm √(13)}.

Explanation:

Step 1:

To solve for x in a polynomial equation, we use the formula


x=\frac{-b \pm \sqrt{b^(2)-4 a c}}{2 a}.

Here a is the coefficient of
x^(2), b is the coefficient of
x and c is the coefficient of the constant term.

In the given equation,
a = 1, b = -4, c = -9.

Step 2:

Substituting the values of a, b, and c in the equation, we get


x=\frac{-b \pm \sqrt{b^(2)-4 a c}}{2 a} =\frac{-(-4) \pm \sqrt{(-4)^(2)-4 (1)(-9)}}{2 (1)} = (4 \pm √((16+36))/(2 ).


(4 \pm √((16+36))/(2 ) = (4 \pm √((52))/(2 ) = (4 \pm2 √((13))/(2 )= {2 \pm √(13)}.

So the answer is option A.
x = {2 \pm √(13)}.

User John Ellinwood
by
5.2k points