Question

at constant atmospheric pressure, the temperature of a gas that occupies the volume of 5.30 L is 298 K. what is the temperature of the gas if it is allowed to expand to 7.60 L?

Answer 1

The new temperature of the gas is 427K

Step-by-step explanation:

In this case we use Charles's Law according to which the volume and temperature of a certain amount of gas are related, keeping the pressure constant.

V1 / T1 = V2 / T2

5,30L/298K=7,60L/T2

T2=7,60L/(5,30L/298K)=427,32K