Answer:
Explanation:
The green triangle is JKL, right? You have plotted it correctly.
Now, for the reflection about x = -1:
First, imagine or draw the line x = -1. It is a line parallel to the y - axis and passing through the point (x,y) = (-1,0)
As the reflection is about a line parallel to the y - axis, the y co-ordinates of the original and reflected figures will be the same. Only the x co-ordinates of the reflected figure would change from the original one.
The formula to compute the x co-ordinate of the reflected geometry is:

Applying this formula to J(2,-1):

∴J' ≡ (-4,-1)
Similarly,
K' ≡ (-6,-5)
L' ≡ (-5,1)