Question

Oxygen 22 has a half life of 2.25 seconds. What percent of the sample is left after 2.25 seconds?

Answer 1

So we got 50% left after 2.25 seconds

Step-by-step explanation:

The left sample is given by

`m=m_(0).2^(-t)/(T)`

where T is the half-life

After 2.25 s

`m=m_(0).2^(-2.25)/(2.25)=m_(0).(1)/(2)`

Answer 2

50 because it’s a ratio problem

Step-by-step explanation: