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Approximate square root of 35 using an appropriate linear approximation.

Approximate square root of 35 using an appropriate linear approximation.-example-1
User Neekey
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1 Answer

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3 votes

Answer:

5.91

Explanation:

35 is between the perfect squares 25 and 36.

√25 = 5

√36 = 6

/ 5 25 \

| d 10 |

1 < x 35 > 11

| 1 |

\ 6 36 /

11/1 = 10/d

11d = 10

d = 0.909

√35 = 5 + d = 5.909

√35 = 5.91

User Ramasamy Kanna
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