Question

12 (2 points) As a final problem for the week Snape thinks we should incorporate something from a previous week, hydrates perhaps. Suppose we have a compound that is 4.330 % Li, 22.10 % Cl, 39.89 % O, and 33.69 % H2O. What is the compounds formula

Answer 1

The formula is = LiClO4.(H2O)3

Step-by-step explanation:

Moles =\frac {Given\ mass}{Molar\ mass}

% of Li = 4.330

Molar mass of Li = 6.941 g/mol

% moles of Li = \frac{4.330}{6.941} = 0.62382

% of Cl = 22.10

Molar mass of Cl = 1.00784 g/mol

% moles of Cl = \frac{22.10}{35.453} = 0.62336

% of O = 39.89

Molar mass of O = 15.999 g/mol

% moles of O = \frac{39.89}{15.999} = 2.49328

% of H₂O = 33.69

Molar mass of H₂O = 18.01528 g/mol

% moles of H₂O = \frac{33.69}{18.01528} = 1.87007

Taking the simplest ratio for Li , Cl, O, and H₂O as:

0.62382 : 0.62336 : 2.49328 : 1.87007

= 1 : 1 : 4 : 3