Answer:
Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)
Explanation:
Step 1: Factor
p(x) = x^3 - 5x^2 - x + 5
p(x) = (x - 5)(x + 1)(x - 1)
Yes, the remainder is 0 so, x-5 is a factor of p(x)
Answer: Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)