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Which expression correctly shows x^6+2x^3+1 factored completely over the integers?

a. (x^2+1)(x4−x^2+1)

b. (x^3+1)2

c. (x+1)(x^2−x+1)

d. (x+1)2(x^2−x+1)2

2 Answers

2 votes
Option D is the answer!
User Andrey Borisko
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Answer:

Option D, (x + 1)^2(x^2 - x + 1)^2

Explanation:

Step 1: Factor

x^6 + 2x^3 + 1

(x + 1)^2(x^2 - x + 1)^2

Answer: Option D, (x + 1)^2(x^2 - x + 1)^2

User Mergeconflict
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4.9k points