Answer:
0.67
Step-by-step explanation:
Given
A1A1= 0.59;
A1A2= 0.16;
A2A2 = 0.25
p =Frequency of (A1)
q = freq (A2)
p = freq(A1A1) + (1/2) freq(A1A2)
= 0.59 + (1/2)(0.16) = 0.67.
0.67 is the observed allele frequency (p) of the A1 allele.
q= freq(A2A2) + (1/2) freq(A1A2)
or directly
q = 1-p = 0.33