Answer: at sixteen dollars per adult ticket and eight dollars per children ticket, the total cost of three adult tickets and eight children tickets is $112
Explanation:
For proper comprehension sake, we can solve a similar question and then apply the same tactics in solving this particular question:
Now, consider that a basketball costs $20 and a soccer ball costs $30. We are required to write an expression to find the total cost of six basketballs and four soccer balls:
Since 1 basketball costs $20 and 1 soccer ball costs $ 30;
We can use "x" to denote the number of basketballs and "y" to denote the number of soccer balls.
We can use the expression below to determine the total cost of the two categories of balls.
20x + 30y
Since we are required to find the cost of 6 basketballs and 4 soccer balls, we will substitute accordingly:
(20 × 6) + (30 × 4)
= (120 + 120)
= 240 balls altogether
We can then, apply this principle to the previous question we were asked in order to find the total cost of 3 adult tickets and 8 children tickets.
Since an adult ticket costs $16 each and children ticket costs $8 each;
The cost of 3 adult tickets and eight children tickets can be determined from the expression:-
3x + 8y (where "x" is the cost of an adult ticket and "y" is the cost of a single children ticket)
Substituting accordingly:-
(3 × 16) + (8 × 8)
= 48 + 64
= $112
Therefore the total cost of three adult tickets and eight children tickets is $112