Question

7. What are the zeroes of the function f(x)= x(x+2)(x-1) ? Select all that apply. (3 points)

x=-2
x=-1
Ox=0
x=1
x=2
x=3

Answer 1

x=0,

x=-2,

x=1

Explanation:

f(x)= x(x+2)(x-1)

If x=0 then f(0)=0(0+2)(0-1)=0

If x=-2 then f(-2)=-2(-2+2)(-2-1)=-2*0 (-3)=0

If x=1 then f(1)=1(1+2)(1-1)=1*3*0=0