Question

Which reactant is limiting?


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Answer 1

• 1. Iodine is the limiting reactant

• 2.
  `6molAlI_3`

Step-by-step explanation:

1. Balanced chemcial equation:

`2Al+3I_2\rightarrow 2AlI_3`

2. Theoretical mole ratio

It is the ratio of the coefficients of the reactants in the balanced chemical equation:

`(2molAl)/(3molI_2)`

3. Actual ratio

It is ratio of the moles available to reat:

`(9molAl)/(9molI_2)`

4. Comparison

`(9molAl)/(9molI_2)>(2molAl)/(3molI_2)`

Then, there are more aluminum available than what is needed to react with the 9 moles of iodine, meaning that the aluminum is in excess and the iodine will react completely, being the latter the limiting reactant.

Conclusion: iodine is the limiting reactant.

5. How much aluminum iodide will be produced?

Use the theoretical mole ratio of aluminum iodide to iodide:

`(2molAlI_3)/(3molI_2)* 9molI_2=6molAlI_3\leftarrow answer`