Question

A relay microchip in a telecommunications satellite has a life expectancy that follows a normal distribution with a mean of 93 months and a standard deviation of 3.3 months. When this computer-relay microchip malfunctions, the entire satellite is useless. A large London insurance company is going to insure the satellite for 50 million dollars. Assume that the only part of the satellite in question is the microchip. All other components will work indefinitely.

(a) For how many months should the satellite be insured to be 90% confident that it will last beyond the insurance date? (Round your answer to the nearest month.)
months(b) If the satellite is insured for 84 months, what is the probability that it will malfunction before the insurance coverage ends? (Round your answer to four decimal places.)
(c) If the satellite is insured for 84 months, what is the expected loss to the insurance company? (Round your answer to the nearest dollar.)
$
(d) If the insurance company charges $3 million for 84 months of insurance, how much profit does the company expect to make? (Round your answer to the nearest dollar.)
$

Answer 1

Explanation:

Wow im not sure

Answer 2

A. The satellite should be insured for 97 months to be 90% confident
B. The probability that it will malfunction before the insurance coverage ends = 0.0032 or 0.32%

C. Expected Loss = 160,000

D. Expected Profit = 2,840,000

How do we find the various duration?

A. The duration for which the satellite should be insured to be 90% confident

Lets use the formula:

X = μ + Z×σ

X = 93 + 1.2816 × 3.3

X = 93 + 4.22928

X = 97.22928

B. Z = (X−μ)/σ

Z = (84−93)/3.3

Z = −9/3.3

Z = −2.7273

P(X < 84) = P(Z < −2.7273) = 0.0032, or about 0.32%

C. Expected Loss = Probability of Malfunction × Insurance Coverage

Expected Loss = 0.0032 × 50,000,000​

Expected Loss = 160,000

D. Expected Profit = Revenue - Expected Loss

Expected Profit = 3,000,000 − 160,000

Expected Profit = 2,840,000

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