Answer:
B. An attractive force of 2.3*10^-4 N
Step-by-step explanation:
As we know by Coulomb's law that the electrostatic force between two charges is given as

here we know that


r = 9.0 m
now we have


since both charges are opposite charges so they will attract each other by the force we calculated above so correct answer will be
B. An attractive force of 2.3*10^-4 N