Factor completely 3x^3 + 3x^2 − 18x. 3x(x + 3)(x + 2) 3x(x + 3)(x − 2) 3x(x − 3)(x + 2) 3x(x − 3)(x − 2)

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asked May 16, 2021 48.1k views

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Factor completely 3x^3 + 3x^2 − 18x.

3x(x + 3)(x + 2)
3x(x + 3)(x − 2)
3x(x − 3)(x + 2)
3x(x − 3)(x − 2)

Mathematics
middle-school

Ederag asked

by Ederag

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6 votes

Answer:

3x(x + 3)(x − 2)

Paul Leader answered May 18, 2021

by Paul Leader

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4 votes

Answer:

3x(x + 3)(x − 2)

Explanation:

$3x( {x}^(2) + x - 6)$

$3x( {x}^(2) - 2 x+ 3x - 6)$

$3x( \: x(x - 2) \: 3(x - 2) \: )$

3x(x + 3)(x - 2)

Alexfr answered May 20, 2021

by Alexfr

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