Question

two-point charges are 10.0 cm apart and have charges of 2.0 uc and -2.0uc respectively What is the magnitude of the electrical field at the midpoint between the two charges?

Answer 1

Electric field due to two charges is given as

`E = 1.44 * 10^7 N/C`

Step-by-step explanation:

As we know that two charges are opposite in nature

So the electric field at the mid point of two charges will add together

so the net field is given as

`E = 2(kq)/(r^2)`

now we have

`q = 2* 10^(-6) C`

`r = 5 cm = 0.05 m`

now we have

`E = 2((9* 10^9)(2* 10^(-6)))/(0.05^2)`

`E = 1.44 * 10^7 N/C`