Question

When 4.008 g of sulfur is burned completely in abundant air, it combines with oxygen to form a single gaseous product with a total mass of 10.008 g. The mass percent of sulfur in the product is % (2 dec places). The mass percent of oxygen in the product is % (2 dec places).

Answer 1

Answer: The mass percent of sulfur and oxygen in the compound is 40.05 % and 59.95 % respectively

Step-by-step explanation:

To calculate the mass percentage of element, we use the equation:

`\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{Mass of compound}}* 100`

• For sulfur:

Mass of sulfur = 4.008 g

Mass of compound = 10.008 g

Putting values in above equation, we get:

`\text{Mass percent of sulfur}=(4.008g)/(10.008g)* 100=40.05\%`

• For oxygen:

Mass of oxygen = [10.008 - 4.008] = 6 g

Mass of compound = 10.008 g

Putting values in above equation, we get:

`\text{Mass percent of oxygen}=(6g)/(10.008g)* 100=59.95\%`

Hence, the mass percent of sulfur and oxygen in the compound is 40.05 % and 59.95 %