Question

17) List the ways five dogs a Beagle, a Collie, a Greyhound, a Poodle and a

Scottie can be put in pairs without counting alternate orders. How many pairs
are there? Is this a combination or permutation?

Answer 1

• 10 pairs

• It is a combination

Step-by-step explanation:

This is a combination because the order does not matter: the Beagle - Collie couple is the same as the Collie - Beagle couple, so it is only counted once.

The formula for combinations is:

`C(m,n)=(m!)/(n!\cdot (m-n)!)`

For five diffferent dogs to be put in pairs, the number of different pairs is:

`C(5,2)=(5!)/(2!\cdot (5-2)!)=(5* 4)/(2)=10`