Question

A current of 23.0 mA is maintained in a single circular loop with a circumference of 1.50 m. A magnetic field of 0.310 T is directed parallel to the plane of the loop. What is the magnitude of the torque exerted by the magnetic field on the loop?

Answer 1

Answer: The magnitude of torque is 1.28Nm

Explanation: Please see the attachments below

Answer 2

0 Nm

Step-by-step explanation:

The magnetic dipole moment, μ, is the product of the current and the area of the loop.

`\mu = IA`

The torque is given by

`\tau = \mu B\sin\theta`

where B is the magnetic field and θ is the angle between the field and the loop.

From the question, the field is parallel to the plane of the loop. Hence,

θ = 0°.

`\tau = \mu B\sin0^\circ = 0 \text{ Nm}`