Answer:
0.875 is the required probability.
Explanation:
We are given the following in the question:
Probability Billy would pass atleast one test = 0.9
![P(A\cup B) = 0.9](https://img.qammunity.org/2021/formulas/mathematics/college/jgc0no21xty72vywydcfvas2dotluc2tbw.png)
Probability Billy would pass both test = 0.7
![P(A\cap B) = 0.7](https://img.qammunity.org/2021/formulas/mathematics/college/747s3dav61qfd2xuubys04jl12mymcog9n.png)
The two test are equally difficult.
![P(A) = P(B)](https://img.qammunity.org/2021/formulas/mathematics/college/fa999eh5di9afb6owixfv78vye2m2dufuq.png)
For independent events we can write that
![P(A\cup B) = P(A) + P(B) -P(A\cap B)\\0.9 = 2P(A) - 0.7\\2P(A) = 1.6\\P(A) = P(B)=0.8](https://img.qammunity.org/2021/formulas/mathematics/college/28r40jqi3rlrtt8gsgwinkhb46osc3i6iu.png)
We have to find the conditional probability that Billy passing test 2 given the event that he passes test 1.
![P(B|A) = (P(B\cap A))/(P(A)) = (0.7)/(0.8) = 0.875](https://img.qammunity.org/2021/formulas/mathematics/college/ex5vsrgtgva758fblxvd30orxhrda29i64.png)
0.875 is the conditional probability of Billy passing test 2 given the event that he passes test 1