Question

Ammonia can also be synthesized by the reaction: 3H2(g)+N2(g)→2NH3(g) What is the theoretical yield of ammonia, in kg, that we can synthesize from 5.22 kg of H2 and 31.5 kg of N2? Express the mass in kilograms to three significant figures.

Answer 1

`29.6kgNH_3`

Step-by-step explanation:

Hello,

In this case, it is firstly necessary to know the limiting reactant via the shown below procedure:

`n_(N_2)^(available)=31.5kgN_2(1kmolN_2)/(28kgN_2)=1.125kmolN_2`

`n_(N_2)^(consumed\ by\ H_2)=5.22kgH_2*(1kmolH_2)/(2kgH_2)*(1kmolN_2)/(3kmolH_2)=0.87kmolN_2`

In such a way, the hydrogen is the limiting reagent as 5.22 kg of it do not consume all the available nitrogen, therefore, the theoretical yield of ammonia turns out as shown below:

`m_(NH_3)=0.87kmolN_2*(2kmolNH_3)/(1kmolN_2)*(17kgNH_3)/(1kmolNH_3)=29.6kgNH_3`

Best regards.