Answer:
The Diameter of an atom that fits into the FCC is 2r,
Which leads to the final steps of 0414R
Step-by-step explanation:
The diameter of an atom that will fit into the FCC site is (2r) which differentiates length edge unit cell for the radii of two atoms that are seen on both side of the site (R); which is 2r = a – 2R
The FCC is also a part of R, therefore a=2R √2
Solving for R, the equation is, r =a-2R/2 =2R√2-2R/2 =0414R