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Find the value of x to the nearest tenth.

Find the value of x to the nearest tenth.-example-1
User Barthelemy
by
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1 Answer

3 votes

Answer:

9.4

Explanation:

The law of cosines tells you ...

c^2 = a^2 + b^2 -2ab·cos(C)

where a and b are the side lengths on either side of angle C, and c is the side opposite that angle. For the values given here, we have ...

c^2 = 8^2 +15^2 -2·8·15·cos(33°) ≈ 87.7191

x = c ≈ √87.7191 ≈ 9.4 . . . . . the side opposite the given angle

The value of x is about 9.4.

Find the value of x to the nearest tenth.-example-1
User Swordholder
by
3.8k points