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2 votes
Solve systems of equations

-x^2-4x+y=0
-x^2+9x+y+13=0

User Alexrnov
by
6.6k points

1 Answer

7 votes

Answer:

I solve it by substitution

y=x^2+4x

-x^2+9x+(x^2+4x)+13=0

13x+13=0

13x=-13

x= -13/13

x= -1

y=x^2+4x=1-4

y= -3

Explanation:

User Pkalinow
by
6.8k points
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