Answer:
The probability that the student will select a card that has both the same number in the ones place in the tens place is 0.08
Explanation:
To solve this exercise we have to know that the probability is calculated by dividing the number of favorable events by the number of possible events.
f = favorable events
we will count how many numbers between 1 and 50 have the same number in the ones place in the tens place
11 ; 22 ; 33 ; 44
as we can see there are 4 numbers
f = 4
p = possible events
the number of possible events is given by the number of cards in the deck
p = 50
4/50 = 0.08
The probability that the student will select a card that has both the same number in the ones place in the tens place is 0.08