Question

A metal alloy weighing 5kg and containing 22% iron melted and mixed with 12 kg of a different alloy which contains 90% iron. What percent of the resulting alloy is iron?

Answer 1

70%

Explanation:

Given the weight of the first alloy as 5kg(22% iron) and the second as 12kg(90% iron:

#First, we find the weight in kgs of the iron in both alloys:

`I_a=0.22* 5.0kg\\\\\\=1.1kg\\\\I_b=0.90* 12kg\\\\=10.8kg\\\\I_a+I_b=1.1+10.8=11.9kg`

Hence, the weight of iron in the resulting alloy is 11.9kg.

#From the given info,the total mass of the alloy is 5+12=17kg

Therefore, the % of iron is calculated as :

`\% Iron=I_(a+b)/T_m\\\\=(11.9)/(17)* 100\%\\\\=70\%`

Hence, 70% of the resulting alloy is iron.